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2x^2-200x+3920=0
a = 2; b = -200; c = +3920;
Δ = b2-4ac
Δ = -2002-4·2·3920
Δ = 8640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8640}=\sqrt{576*15}=\sqrt{576}*\sqrt{15}=24\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-24\sqrt{15}}{2*2}=\frac{200-24\sqrt{15}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+24\sqrt{15}}{2*2}=\frac{200+24\sqrt{15}}{4} $
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